Pallet Configuration Calculator

What changes when one layer mixes orientations?

A uniform grid puts every carton in the same direction. This configuration tool can place identical cartons at both 0 and 90 degrees on the same layer. That extra freedom sometimes uses a residual strip that a uniform grid leaves empty. The result still represents a two-dimensional arrangement of rectangular outside footprints. It does not rearrange cartons in three dimensions, reduce their measured dimensions or evaluate interlocking strength. Treat the diagram as a layer proposal with explicit geometric assumptions.

Use the outside length and width of a packed case. Pallet length and width define the available rectangle. Enter equal gaps between cases and edge clearance when they are required, rather than assuming that a nominal pallet footprint provides spare space. Rotation should be allowed only if the case and its contents may be turned in the horizontal plane. It does not mean that a case can be placed on its side or upside down.

A five-case pattern you can verify by hand

Consider a 1200 × 1000 mm pallet and cases measuring 600 × 400 mm, with rotation enabled and zero added gap or edge clearance. The unrotated uniform grid holds floor(1200 / 600) × floor(1000 / 400) = 2 × 2 = 4 cases. The all-rotated grid holds floor(1200 / 400) × floor(1000 / 600) = 3 × 1 = 3. A mixed arrangement can hold five cases: put three rotated cases in a 600 mm deep strip, then two unrotated cases in the remaining 400 mm deep strip.

Each rectangle remains inside the 1200 × 1000 boundary. Cases meet at edges but do not overlap. Five case areas of 600 × 400 mm sum to 1,200,000 square millimetres, exactly the pallet's area. The area upper bound is floor(1,200,000 / 240,000) = 5, so the valid five-case construction proves the count for these exact zero-clearance inputs. This is a geometric proof, not a statement about stability, carton compression or pallet load rating.

Why a small clearance can remove a case

The five-case pattern has no spare area. Adding a 10 mm gap makes the three-case strip require 3 × 400 + 2 × 10 = 1220 mm, exceeding the pallet length. Adding 10 mm edge clearance on all four sides leaves a usable rectangle of 1180 × 980 mm. Its area is 1,156,400 square millimetres, giving an area upper bound of four 240,000-square-millimetre cases. That ceiling does not itself prove that four fit with every requested gap; run the search and inspect its actual candidate.

Report both the tight comparison and the operational-input result with their settings. Do not keep a zero-clearance drawing while labelling it as a layout that includes spacing. If carton bulges or wrapping increase the footprint, update the case dimensions before searching. A small increase can cross a fit boundary and change a whole strip of cases rather than produce a gradual percentage reduction.

Read the search status before using the count

The engine combines complete mixed-strip enumeration with several deterministic MaxRects rules. It keeps valid candidate coordinates and checks that rectangles stay inside the usable boundary, do not overlap, respect the entered gap and use allowed orientations. Those checks establish the validity of the returned geometry. They do not always prove that another search could not find a larger count.

When the engine reaches a valid upper bound or matches a supported independently verified fixture, it can label the count proven optimal. Otherwise the result is best found. The difference matters: a best-found count is an achievable geometric proposal under the model, while its displayed upper bound is a possible ceiling. A gap between them is uncertainty about optimality, not permission to load the ceiling. The browser work cap also limits search output; hitting a cap does not provide an optimality proof.

Turn the layer proposal into a stack calculation

This tool answers the layer question. To calculate total cases, first establish an allowed number of complete layers using a height limit and any entered weight constraints. For illustration, five cases per layer, 300 mm case height, 162 mm pallet base height and a 1400 mm total height limit allow floor((1400 − 162) / 300) = 4 complete layers. The result is twenty cases and a loaded height of 1362 mm, assuming no added interlayer thickness.

If each case weighs 18 kg and an example pallet tare is 30 kg, those twenty cases and the pallet weigh 390 kg before other materials. The 30 kg tare is a stated hypothetical input, not a specification for every industrial pallet. A real gross limit or payload rating must come from the relevant equipment or supplier. Case count and rectangular utilization cannot establish that twenty cases are safe to stack.

Review the physical arrangement and record it

Check whether cases may rotate, how the receiving operation identifies their labels, and whether the proposed orientations remain compatible with the packaging. Evaluate stacking strength, handling, allowed overhang and securing requirements separately with the responsible operation. Identical rectangular cases are the model's input; mixed case sizes or irregular bundles require a different model or separate planning work. A high area utilization does not measure compression strength or resistance to movement during transport.

Keep the input record, coordinates, count, utilization definition and status together. A teammate should be able to locate every case's rectangle and repeat the same search. Changing units should describe the same physical dimensions; for an independent check, convert inches to millimetres using exactly 25.4 mm per inch. Avoid rounding away decimals near boundaries. Read the methodology and the public layout engine for the algorithm contract and its regression fixtures. The site's calculation examples remain planning aids rather than certifications.